Python Cheatsheet Cheat Sheet

name = "007wins"
print (name.upper())
print (name.lower())
print (name.capitalize())
print (name.title())

#write the function that returns the largest number in a list
#name: maxlist
#argument:list
#returns the largest value in the list


def maxlist(list):
    maxvalue = list[0]
    for item in list:
        if item > maxvalue:
            maxvalue = item

    return maxvalue


mylist = [1,2,3,4,55,66,777,0,1]
print(maxlist(mylist))

while True:
    
    user_radius = input("What is the radius?")
    radius = float(user_radius)
    pi = 3.1415
    area= pi radius * 2
    print ("The area of the circle is", area

mystring = "hello"
print (mystring)
firstname = input( "what is your first name?")
lastname = input( "what is your last name?")
fullname = firstname + " " + lastname
print (fullname)

letternumber = int(input( " what is letter number? " ))
if letternumber >len(fullname):
    print ( " invalid letter number, try again! " )
else:

    letter = ( fullname[letternumber] )
    print (letter)

    numberletter = int(input( "how many times to print letter " ))

    if numberletter >100:
       print ( " too many letters to print! " )
    else:
        print (letter * numberletter )

#write a function that returns the largest of two values
#name : max2
#agruments: num1, num2
# return: largest value

# write a functrion that returns the largest of three values
# name : max3
#agrument: num1, num2, num3
# return: largest value

def max2(num1,num2):
    if num1 >= num2:
        max_value = (num1)
    if num2 > num1:
        max_value = (num2)
    return max_value

num1 = input('Enter the the first value')
num2 = input('Enter the the second value')
print (max2(num1,num2))





def max3(num1,num2,num3):
    if num1 >= num2 and num1 >= num3:
        max_value = (num1)
    if num2 > num1 and num2 >= num3:
        max_value = (num2)
    if num3 >= num2 and num3 >= num1:
        max_value = (num3)
        
    return max_value

num3 = input('Enter the the third value')
print (max3(num1,num2,num3))