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Sample space
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The set of all possible outcomes (e.g 1,2,3,4,5,6 on a normal dice)
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Equally likely outcomes
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A situation in which all outcomes have the same chance of occuring
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Mutually exclusive events
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These events have no outcomes in common
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Non mutually exclusive events
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These events have at least one outcome in common
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Luke's chance of clearing the high jump is 7/10. Luke's chance of not clearing the high jump is?
1 (10) - 7/10 = 3/10 P(not clearing the high jump)
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We have a bag with 9 red marbles, 2 blue marbles, and 3 green marbles. What is the probability of not selecting a blue marble?
Number of total marbles = 14
Blue marbles = 2 1 (14) - 2 = 12/14 P(non blue marbles) |
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What is the time in London, when it is 9am in Sydney? (Sydney is 10 hours ahead)
London time = Sydney time - 10 hours
9am - 10h = 11pm in London |
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What is the time in Sydney, when it is 9am in London? (London is 10 hours behind)
Sydney time = London time + 10 hours
9am + 10h = 7pm in Sydney |
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Rectangular prisms
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Length x Width x Height
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Triangular prisms
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Area of triangle x Height
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Any other prism
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Area x Height (area of the cross section and height is the height of the prism)
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Rectangle
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Width x Height (or wh)
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Square
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a² (a = length of side)
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Triangle
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1/2 x Base x Height (or bh)
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Trapezium
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1/2 x (side a+ side b)
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Parallelogram
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Base x Height (or bh)
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Rhombus/Kite
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Side A x Side B / 2
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Cubic Millimetres
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mm³
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Cubic Millimetres
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cm³
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1cm³ = 1000m³
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Cubic Metres
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m³
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1m³ = 1000 000 cm³
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Mililitre
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mL
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1mL = 1cm³
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Litres
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L
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1L = 1000ml = 1000cm³
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Kilolitres
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kL
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1kL = 1000L = 1m3
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Megalitres
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ML
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1ML = 1000kL = 1000 000L
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m x m
m2
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5 x n x n x n
5n3
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30a / 2a
Divide the numbers first, so 30 / 2 = 15.
Next, cancel out the pronumerals. A goes into A, which gives us just 15. |
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12ab / 6a2
Divide the numbers first, so 12 / 6 equals 2. Next, cancel out the pronumerals. A goes into A but B does not go into A. This gives us 2b / a.
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3a + 12
3 x a + 3 x 4 is the expanded form.
The factorised form is 3(a + 4). |
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6m + 9
First, find the HCF. In this case, it is 3.
Put the HCF out the front of a pair of brackets. Find what the HCF is multiplied by to get each term. So we end up getting 3(2m + 3) |
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5x - 2y - 3x + 7y
Move the terms with the same pronumeral next to each other. So we get 5x - 3x - 2y + 7y
Simplify and you get 2x + 5y |
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7ab - 3bc + 2ab
Move the terms with the same pronumeral next to each other. So we get 7ab + 2ab - 3bc
Simplify and you get 9ab - 3bc |
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10 x 3n
10 x 3 = 30
30 x n = 30n |
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20n x 3mn
20 x 3 = 60
60 x n x n x m = 60n2m |
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5(y + 3) + 2y
5 x y = 5y
5 x 3 = 15 5y + 2y = 7y Expanded form is 7y + 15 |
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3(a + 4) + 2(5 - a)
3 x a = 3a
3 x 4 = 12 2 x 5 = 10 2 x a = 2a 3a +- 2a = a 12 + 10 = 22 Expanded form is a + 22 |
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Cheatography n. The art of mapping complex subjects into clear, instantly navigable reference guides.