|
Boyle's Law
|
PinitialVinitial=PfinalVfinal
|
|
Charles's Law
|
Vi÷Ti = Vf÷Tf
|
|
Combined Gas Law
|
PiVi÷Ti = PfVf÷Tf
|
|
Avogadro's Law
|
Vi÷ni=Vf÷nf
|
|
Ideal Gas Law
|
PV=nRT
|
|
Dalton's Law of Partial Pressure
|
Ptotal=P1+P2+P3...
|
|
Partial Pressure
|
Pgas(atm)=(total pressure x molesgas)÷total moles
|
|
PP when volumes are different
|
Ptotal=P1(atmxV1÷Vtotal)+P2(atmxV2÷Vtotal)...
|
|
Mole fraction
|
moles of gas ÷ total moles
|
|
Wet Gas
|
Pwet gas=Ptotal-PH2O
|
|
then use PV=nRT to solve for variables
|
|
Van der waal's equation
|
P=[(nRT)÷(V-nb)] - [(a*n2)÷(V2)]
|
|
When comparing real gases
|
a gas with a larger "a" value will require the largest correction to account for intermolecular forces
|
|
a gas with a smaller "b" value will behave most ideally at high pressures
|
|
|
If Vdw's pressure is lower than the ideal pressure, attractive forces dominate
|
|
|
If Vdw's pressure is higher than ideal pressure, repulsive forces dominate
|
|
|
Real Gas Behavior
|
attractive forces between molecules cause a decrease in pressure
|
|
As molecules increase in size deviations from ideal behavior become apparent at relatively HIGH temps
|
|
|
In general, most gases behave most ideally at HIGH temps and LOW pressures
|
|
1 atm=
|
1 atm (R= .08206)
|
|
760 mmHg (R= 62.364)
|
|
|
760 torr
|
|
|
1.013x105 Pa
|
|
|
101.3 kPa
|
|
|
29.92 inches Hg
|
|
|
14.69 psi
|
|
|
1.01325 bar
|
|
Mole ratio = Volume ratio
|
2A+3B=AB
|
|
2A:3B
|
|
|
2mL A:3mL B
|
|
Temperature
|
If temperature is increased, Pressure and KE increase by a factor of Tf÷Ti and rms increases by a factor of √Tf÷Ti
|
|
Volume
|
If volume is increased, Pressure increases by a factor of Vi÷Vf while KE and rms increase by a factor of 1 (because they are not affected))
|
|
Moles
|
If moles are increased, pressure increases by a factor of nf÷ni, while KE and rms increase by a factor of 1 (no change)
|
|
Ideal Gas Law
|
PV=nRT
|
|
STP
|
0 degrees celcius, 273 degrees Kelvin, 1 atm, 22.4 L/mol
|
|
Density
|
d=MP÷RT where M is molar mass
|
|
Volume
|
When not given volume, but told to assume ideal gas behavior, use V=1L
|
|
G1=gas 1
|
G2=gas 2
|
|
Average Kinetic Energy
|
KEG1 = KEG2 when TG1=TG2
|
|
Molecular Speed
|
√u2 = √3RT÷M where M is the molar mass
|
|
√u2G1 ÷ √u2G2 = √MG2 ÷ √MG1
|
|
|
Rate
|
d/dx G1 ÷ d/dx G2 = √MG2 ÷ √MG1
|
|
Time
|
tG2 ÷ tG1 = √MG2 ÷ √MG1
|
No comments yet.
Cheatography n. The art of mapping complex subjects into clear, instantly navigable reference guides.